2x^2+4x+8=5

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Solution for 2x^2+4x+8=5 equation:



2x^2+4x+8=5
We move all terms to the left:
2x^2+4x+8-(5)=0
We add all the numbers together, and all the variables
2x^2+4x+3=0
a = 2; b = 4; c = +3;
Δ = b2-4ac
Δ = 42-4·2·3
Δ = -8
Delta is less than zero, so there is no solution for the equation

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